题目类型：
问答题
题目内容
计算∫01[1/(1+ex)]dx．
正确答案
1-ln(1+e)+ln2 分析 ∫01[1/(1+ex)]dxfoI=∫01[(1+ex-ex)/(1+ex)]dx=∫01[1-ex/(1+ex)]dx =∫01dx-∫01[1/(1+ex)]d(1+ex) =(-ln(1+e))|01=1-ln(1+e)+ln2．